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Asked by Carol

How many mL of 1.67M sulfuric acid would it take to neutralize 26.6mL of 3.12M sodium hydroxide?
9 years ago

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Answered by DrBob222
2NaOH + H2SO4 ==> 2H2O + Na2SO4

mols NaOH = M x L = ?
Use the coefficients in the balanced equation to convert mols NaOH to mols H2SO4. (You can see mols H2SO4 = 1/2 mols NaOH)
Then M H2SO4 = mols H2SO4/L H2SO4. You know M and mols, solve for L and convert to mL.
9 years ago

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