Asked by Anonymous
A stone propelled from a catapult with a speed of 50m/s attains a height of 100m.Calculate:(a)the time of flight?
Answers
Answered by
Damon
Just as long as anything else that goes up 100 meters and falls
Which is twice as long as it takes to fall 100 meters
h = (1/2) g t^2
100 = 4.9 t^2
t = 4.52 seconds to fall
so about 9 seconds
Which is twice as long as it takes to fall 100 meters
h = (1/2) g t^2
100 = 4.9 t^2
t = 4.52 seconds to fall
so about 9 seconds
Answered by
Sabuda
time of fligt
t=2*√2H/g
=2*√2*100/10
=2*√200/10
=2*√20
=2*4.47
=8.94s
t=2*√2H/g
=2*√2*100/10
=2*√200/10
=2*√20
=2*4.47
=8.94s
Answered by
abubakar
am asking question a stone propelled from a catapult with a speed of 50 m/s attains a height of 100m calculate (a)the range attained
Answered by
Anonymous
(a)the angle of projection (b) the range attained
Answered by
Awal
T=8.945
Answered by
Angelo
I don't get why it is multiplied by 2
Answered by
Aderinola
how are we going to calculate the angle of projection and the range attained
Answered by
Salisu
Which Formular Will You Use To Get The Angle Of Projection?
Answered by
David
Tether=sin-1(Tg/2u)
Answered by
FUNMILAYO
A STONE IS PROPELLED FROM A CATAPULT WITH A SPEED OF 500MS ATTAINS THE HEIGHT OF 100M.CALCULATE,a:THE TIME OF FLIGHT,b:THE ANGLE OF PROJECTION,c:THE RANGE ATTAINED.
Answered by
Anonymous
A. time of flight
t=2*√2H/g
=2*√2*100/10
=2*√200/10
=2*√20
=2*4.47
=8.94s
B. The angle of projection
sinø=0.8944
Ø= sin–¹(0.8944)
Ø=63.4314654⁰
Ø ≈ 63.43⁰
C. Range
R=u²sin2ø/g
R=? u=50 , ø=63.4⁰, g= 10
= 50²*sin(2*63.4⁰)/10
=2500*sin(126.8⁰)/10
=250*0.8007
=200.2m
R≈200m
t=2*√2H/g
=2*√2*100/10
=2*√200/10
=2*√20
=2*4.47
=8.94s
B. The angle of projection
sinø=0.8944
Ø= sin–¹(0.8944)
Ø=63.4314654⁰
Ø ≈ 63.43⁰
C. Range
R=u²sin2ø/g
R=? u=50 , ø=63.4⁰, g= 10
= 50²*sin(2*63.4⁰)/10
=2500*sin(126.8⁰)/10
=250*0.8007
=200.2m
R≈200m
Answered by
Smile
A. time of flight
t=2*√2H/g
=2*√2*100/10
=2*√200/10
=2*√20
=2*4.47
=8.94s
B. The angle of projection
sinø=0.8944
Ø= sin–¹(0.8944)
Ø=63.4314654⁰
Ø ≈ 63.43⁰
C. Range
R=u²sin2ø/g
R=? u=50 , ø=63.4⁰, g= 10
= 50²*sin(2*63.4⁰)/10
=2500*sin(126.8⁰)/10
=250*0.8007
=200.2m
R≈200m
t=2*√2H/g
=2*√2*100/10
=2*√200/10
=2*√20
=2*4.47
=8.94s
B. The angle of projection
sinø=0.8944
Ø= sin–¹(0.8944)
Ø=63.4314654⁰
Ø ≈ 63.43⁰
C. Range
R=u²sin2ø/g
R=? u=50 , ø=63.4⁰, g= 10
= 50²*sin(2*63.4⁰)/10
=2500*sin(126.8⁰)/10
=250*0.8007
=200.2m
R≈200m
Answered by
TERNA
I THINK ANONYMOUS MAY BE CORRECT
Answered by
Damilola
Thanks so much for solving this problem already, i appreciate u very much
Answered by
Chizzy
Thanks so much i appreciate
Answered by
Chizzy
Anonymous are right
Answered by
Anonymous
How did you get the tita
Answered by
vickky
Exactly how did you get the theta
Answered by
peace
pls how did u solve the angle of projection
Answered by
Fatima
A stone propeller from a catopon often a gift of 100m calculate
Answered by
Fyjiygtt
Yggdo
Answered by
Seyi
What is the formula used in time of flight
Answered by
Anonymous
Thank you very well
Answered by
Joshua
thanks
Answered by
Precious
A how do i calculate a stone propelled from a catapult with a speed of 50ms attains a height of 100m.calcute the time of flight