Asked by effraim
A 100-g toy car is propelled by a compressed spring that starts it
moving. The car follows the curved track Show that the final speed of the toy car is 0.687 m/s if its initial speed is 2.00 m/s and it coasts up the frictionless slope, gaining 0.180 m in altitude
moving. The car follows the curved track Show that the final speed of the toy car is 0.687 m/s if its initial speed is 2.00 m/s and it coasts up the frictionless slope, gaining 0.180 m in altitude
Answers
Answered by
bobpursley
vf^2=vi^2 + 2gd
g=-9.8m/s^2, d=.180 m, vi given. mass is not needed.
g=-9.8m/s^2, d=.180 m, vi given. mass is not needed.
Answered by
fdf
dfd
Answered by
shd
hsd
Answered by
Kgatliso
use conservation of Mechanical energy formula.
change in ME=0
change in Ek+change in PE=0
1/2mvf^2+mghf=1/2mvi^2 +mghi
1/2(0.100)(0.687)^2+(0.100)(9.81)(0.180)=1/2(0.100)(2.00)^2+(0.100)(9.81)(0)
0.20=0.20
change in ME=0
change in Ek+change in PE=0
1/2mvf^2+mghf=1/2mvi^2 +mghi
1/2(0.100)(0.687)^2+(0.100)(9.81)(0.180)=1/2(0.100)(2.00)^2+(0.100)(9.81)(0)
0.20=0.20
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