Asked by Unknown
A stone is propelled from a catapult with a speed of 50ms-1 ,attains a height of 100m calculate:
1.the time of flight
2.the angle of projection
3.the range
1.the time of flight
2.the angle of projection
3.the range
Answers
Answered by
Unknown3
Do one is solving
Answered by
henry2,
Y^2 = Yo^2+2g*h = 0.
Yo^2+(-19.6)100 = 0,
Yo = 44.3 m/s. = Vertical component of initial velocity.
1. Y = Yo + g*Tr = o.
44.3 + (-9.8)Tr = 0,
Tr = 4.52 s. = Rise time.
Tf = Tr = 4.52 s. = Fall time.
Tr+Tf = 4.52 + 4.52 = 9.04 s. = Time of flight.
2. Yo = Vo*sin A = 44.3.
50*sin A = 44.3,
A = 62.4 Degrees.
3. Range = Vo^2*sin(2A)/g = 50^2*sin(124.8)/9.8 =
Yo^2+(-19.6)100 = 0,
Yo = 44.3 m/s. = Vertical component of initial velocity.
1. Y = Yo + g*Tr = o.
44.3 + (-9.8)Tr = 0,
Tr = 4.52 s. = Rise time.
Tf = Tr = 4.52 s. = Fall time.
Tr+Tf = 4.52 + 4.52 = 9.04 s. = Time of flight.
2. Yo = Vo*sin A = 44.3.
50*sin A = 44.3,
A = 62.4 Degrees.
3. Range = Vo^2*sin(2A)/g = 50^2*sin(124.8)/9.8 =
Answered by
Abdullahi
Don't understand
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