Asked by Unknown
                A stone is propelled from a catapult with a speed of 50ms-1 ,attains a height of 100m calculate: 
1.the time of flight
2.the angle of projection
3.the range
            
            
        1.the time of flight
2.the angle of projection
3.the range
Answers
                    Answered by
            Unknown3
            
    Do one is solving
    
                    Answered by
             henry2,  
            
    Y^2 = Yo^2+2g*h = 0.
Yo^2+(-19.6)100 = 0,
Yo = 44.3 m/s. = Vertical component of initial velocity.
1. Y = Yo + g*Tr = o.
44.3 + (-9.8)Tr = 0,
Tr = 4.52 s. = Rise time.
Tf = Tr = 4.52 s. = Fall time.
Tr+Tf = 4.52 + 4.52 = 9.04 s. = Time of flight.
2. Yo = Vo*sin A = 44.3.
50*sin A = 44.3,
A = 62.4 Degrees.
3. Range = Vo^2*sin(2A)/g = 50^2*sin(124.8)/9.8 =
    
Yo^2+(-19.6)100 = 0,
Yo = 44.3 m/s. = Vertical component of initial velocity.
1. Y = Yo + g*Tr = o.
44.3 + (-9.8)Tr = 0,
Tr = 4.52 s. = Rise time.
Tf = Tr = 4.52 s. = Fall time.
Tr+Tf = 4.52 + 4.52 = 9.04 s. = Time of flight.
2. Yo = Vo*sin A = 44.3.
50*sin A = 44.3,
A = 62.4 Degrees.
3. Range = Vo^2*sin(2A)/g = 50^2*sin(124.8)/9.8 =
                    Answered by
            Abdullahi 
            
    Don't understand 
    
                                                    There are no AI answers yet. The ability to request AI answers is coming soon!
                                            
                Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.