Asked by chisom
a stone propelled from a catapult with a speed of 50ms-1 attains a height of 100m. Calculate the time of flight and the angle of projection
Answers
Answered by
Damon
vertical problem:
v = Vi - 9.81 t
v = 0 at the top
t = Vi/9.81 at the top which is 100 meters
h = Vi t - 4.9 t^2
100 = Vi^2/9.81 - .5*9.81 (Vi^2/9.81^2)
100 = .5Vi^2/9.81
Vi = 44.3 m/s
T = angle up from horizontal
sin T = 44.3/50
T = 62.4 degrees
t = 2 * Vi/9.81 = 2*44.3/9.81 = 9.03 seconds
v = Vi - 9.81 t
v = 0 at the top
t = Vi/9.81 at the top which is 100 meters
h = Vi t - 4.9 t^2
100 = Vi^2/9.81 - .5*9.81 (Vi^2/9.81^2)
100 = .5Vi^2/9.81
Vi = 44.3 m/s
T = angle up from horizontal
sin T = 44.3/50
T = 62.4 degrees
t = 2 * Vi/9.81 = 2*44.3/9.81 = 9.03 seconds
Answered by
Anonymous
Not correct
Answered by
Akinsipe favour
I didn't really understand ur formula and ur parameters but it is OK . the answer was correct.
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