Asked by britnay
if one of the zeros of y=x^2+bx+1 is 1 determine the value of b
anyone understand this and can help me break it down
anyone understand this and can help me break it down
Answers
Answered by
JJ
It means when y = 0 then x = 1
0 = 1^2 + b(1) + 1
0 = 1 + b + 1
Solve for b.
0 = 1^2 + b(1) + 1
0 = 1 + b + 1
Solve for b.
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