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Anonymous
If zeros of p(x)=2x2-7x+k are reciprocals of each other,then find the value of me
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Answered by
Steve
If the roots are a and 1/a, then
a*1/a = k/2
k=2
2x^2-7x+2 has roots
(7±√33)/4
and, it happens that (7-√33)/4 = 4/(7+√33)
Answered by
Anonymous
If zeroes of p(x) = 2x2
– 7x + k are reciprocal of each other, then find the value of k.
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