Asked by Danielle
what are the zeros for 1x^5+2x^4+4x^3+19x^2+9x^2+9x-5?
Answers
Answered by
Steve
5th-degree polynomials are not open to solution in general, so look for low-hanging fruit using synthetic division.
any rational roots must be ±1 or ±5.
no joy there.
not sure how to find the roots analytically. You may have to use some iterative methods. Don't know whether you have studied those yet.
If you go to wolframalpha.com and enter
solve x^5+2x^4+4x^3+19x^2+9x^2+9x-5 = 0
you will get the roots, but not much help in figuring out the exact values using radicals.
any rational roots must be ±1 or ±5.
no joy there.
not sure how to find the roots analytically. You may have to use some iterative methods. Don't know whether you have studied those yet.
If you go to wolframalpha.com and enter
solve x^5+2x^4+4x^3+19x^2+9x^2+9x-5 = 0
you will get the roots, but not much help in figuring out the exact values using radicals.
There are no AI answers yet. The ability to request AI answers is coming soon!