Asked by mike

(a) The solubility of bismuth iodide in water is 9.091 x 10-3 M. Calculate the value of the solubility product. The dissolution products are and
Answered by Anonymous
solubility = (x)*((x*3))^3

x=9.091*10-3

solubility = 1.84*10^-7
Answered by Anonymous
u r the best!
Answered by rex
5.043*10^-7
There are no AI answers yet. The ability to request AI answers is coming soon!