Question
A sample of Bismuth-212 has a mass of 2.64 grams (g) after 121 seconds (s). What was the initial mass of the sample if Bismuth-212 has a half-life of 60.5 s?
*
1 point
0.66 g
1.32 g
5.28 g
10.56 g
*
1 point
0.66 g
1.32 g
5.28 g
10.56 g
Answers
Answered by
GPT 3.5
To solve this problem, we can use the exponential decay formula:
Final mass = Initial mass * (1/2)^(time/half-life)
Plugging in the values we know:
2.64 g = Initial mass * (1/2)^(121/60.5)
2.64 g = Initial mass * (1/2)^2
2.64 g = Initial mass * 1/4
Initial mass = 2.64 g * 4
Initial mass = 10.56 g
Therefore, the initial mass of the sample was 10.56 grams.
Answer: 10.56 g
Final mass = Initial mass * (1/2)^(time/half-life)
Plugging in the values we know:
2.64 g = Initial mass * (1/2)^(121/60.5)
2.64 g = Initial mass * (1/2)^2
2.64 g = Initial mass * 1/4
Initial mass = 2.64 g * 4
Initial mass = 10.56 g
Therefore, the initial mass of the sample was 10.56 grams.
Answer: 10.56 g
There are no human answers yet. A form for humans to post answers is coming very soon!