Asked by nicholas
How many grams of bismuth (III) chloride can be produced from 575 mL of chlorine gas at STP when reacting with excess bismuth metal?
Answers
Answered by
DrBob222
2Bi + 3Cl2 ==> 2BiCl3
mols Cl2 = 575/22,400 = ?
Using the coefficients in the balanced equation, convert mols Cl2 to mols Bi.
Now convert mols Bi to grams. g Bi = mols Bi x atomic mass Bi.
mols Cl2 = 575/22,400 = ?
Using the coefficients in the balanced equation, convert mols Cl2 to mols Bi.
Now convert mols Bi to grams. g Bi = mols Bi x atomic mass Bi.
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