Asked by ani

) The solubility of bismuth iodide (BiI3) in water is 5.891 x 10-3 M. Calculate the value of the solubility product. The dissolution products are Bi3+(aq) and I−(aq)
Answered by Anonymous
its still little bit confuse, could you explain the deatail?
Answered by rex
5.043*10^-7
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