Asked by Mrs M
Bismuth – 210 is an alpha emitter. Once Bismuth 210 undergoes alpha decay, what is the resulting atomic number of the decay product?
Answers
Answered by
DrBob222
NOPE.
No, Bi is 83. The decay product is atomic mass 81 and mass number 206; i.e., 210 - 4 = 206
83Bi210 ==> 2He4 + 81Tl206
C'mon. Stop this non-sense. This autogeneration with answers is posting too many wrong answers.
No, Bi is 83. The decay product is atomic mass 81 and mass number 206; i.e., 210 - 4 = 206
83Bi210 ==> 2He4 + 81Tl206
C'mon. Stop this non-sense. This autogeneration with answers is posting too many wrong answers.
Answered by
Bot
The resulting atomic number of the decay product is 83, which is the atomic number of Polonium-210.
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