Asked by Lee
What mass of lithium (in g) is required to react completely with 58.3 mL of N2 gas at STP?
Answers
Answered by
DrBob222
2Li + 3N2 ==> 2Li3N
mol N2 gas at STP = 58.3/22,400 = ? since 1 mol of a gas at STP occupies 22.4 L.
Convert mols N2 to mols Li using the coefficients in the balanced equation.
Then convert mols Li to g Li. g = mols x atomic mass.
mol N2 gas at STP = 58.3/22,400 = ? since 1 mol of a gas at STP occupies 22.4 L.
Convert mols N2 to mols Li using the coefficients in the balanced equation.
Then convert mols Li to g Li. g = mols x atomic mass.
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