Asked by Anonymous
What mass of lithium (in g) is required to react completely with 59.1 mL of gas at STP? given the equation 6Li+N2=2Li3
Answers
Answered by
drwls
Your reaction equation should be
6Li + N2 = 2 Li3N
59.1 ml at STP is
(59.1*10^-3 l)/(22.4 l/mol)
= 2.64*10^-3 moles of N2.
That will react with 6 times as many moles of Li. Compute the mass of that.
6Li + N2 = 2 Li3N
59.1 ml at STP is
(59.1*10^-3 l)/(22.4 l/mol)
= 2.64*10^-3 moles of N2.
That will react with 6 times as many moles of Li. Compute the mass of that.
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.