Asked by Carter

What mass of lithium (in g) is required to react completely with 57.5mL of N2 gas at STP? Lithium reacts with nitrogen gas according to the following reaction:
6Li(s)+N2(g)→2Li3N(s)

Answers

Answered by DrBob222
mols N2 = 57.5/22,400 = ?
mols Li = 6x that (from the coefficients in the balanced equation).
Then g Li = mols Li x atomic mass Li = ?
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