Asked by Carter
What mass of lithium (in g) is required to react completely with 57.5mL of N2 gas at STP? Lithium reacts with nitrogen gas according to the following reaction:
6Li(s)+N2(g)→2Li3N(s)
6Li(s)+N2(g)→2Li3N(s)
Answers
Answered by
DrBob222
mols N2 = 57.5/22,400 = ?
mols Li = 6x that (from the coefficients in the balanced equation).
Then g Li = mols Li x atomic mass Li = ?
mols Li = 6x that (from the coefficients in the balanced equation).
Then g Li = mols Li x atomic mass Li = ?
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