Li3PO4.
You want (Li^+) = 0.1385M
You want to make this out of Li3PO4. But since Li3PO4 furnishes 3 Li ions for every molecule of Li3PO4, you only need 1/3 that number or 0.1385/3 = ? mols Li3PO4.
Then g Li3PO4 = mols x molar mass.
What mass of lithium phosphate is needed to prepare 500.0 mL of a solution having a lithium ion concentration of 0.1385 M?
3 answers
I did that but got 5.346 g as my answer. Is that correct?
No and partly because I may have led you astray. The numbers I gave you are for 1L of the solution at that concn. You only want 500 mL of that (which I missed on first reading) so you need only 1/2 of your final figure or 5.346/2 = ?.
1 answer