Asked by Kaitlin
How many grams of solid potassium hydroxide are needed to exactly neutralize 10.8 mL of a 1.25 M hydrobromic acid solution
Answers
Answered by
DrBob222
KOH + HBr ==> KBr + H2O
mols HBr = M x L = ?
mols KOH = mols HBr (from the coefficients in the equation).
mols KOH = grams/molar mass. You know molar mass and mols, solve for grams.
mols HBr = M x L = ?
mols KOH = mols HBr (from the coefficients in the equation).
mols KOH = grams/molar mass. You know molar mass and mols, solve for grams.
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