Asked by Anonymous
What mass (in grams) of potassium acetate, KC2H3O2, must be added to 140 mL of 0.010 M acetic acid to form a buffer solution with a pH of 4.5?
(Ka (HC2H3O2)= 1.8 x 10-5)
(Ka (HC2H3O2)= 1.8 x 10-5)
Answers
Answered by
DrBob222
pH = pKa + log(b/a)
4.5 = 4.74 + log(base)/(acid)
4.5 = 4.74 + log(base)/0.01
Solve for (base) in moles/L.
Convert to moles in 140 mL and convert that to grams KC2H2O2.
4.5 = 4.74 + log(base)/(acid)
4.5 = 4.74 + log(base)/0.01
Solve for (base) in moles/L.
Convert to moles in 140 mL and convert that to grams KC2H2O2.
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