Asked by Sandu
How many grams of solid KOH must be added to 100ml of a buffer solution which is 0.1M each with
respect to the weak acid HA and its potassium salt KA in order to make the pH of the solution 6.0?
respect to the weak acid HA and its potassium salt KA in order to make the pH of the solution 6.0?
Answers
Answered by
DrBob222
You have 100 mL x 0.1M = 10 millimols HA and 10 mmols KA.
....HA + KOH = KA + H2O
I...10....0....10........
add.......x.............
C..-x....-x....+x
E...10-x..0....10+x
Substitute the E line into the Henderson-Hasselalch equation and solve for x = millimols KOH that must be added. Convert to grams KOH.
Post your work if you get stuck.
....HA + KOH = KA + H2O
I...10....0....10........
add.......x.............
C..-x....-x....+x
E...10-x..0....10+x
Substitute the E line into the Henderson-Hasselalch equation and solve for x = millimols KOH that must be added. Convert to grams KOH.
Post your work if you get stuck.
Answered by
Sandu
Yes... Got the answer 0.458 g.. Thank you...