You have 100 mL x 0.1M = 10 millimols HA and 10 mmols KA.
....HA + KOH = KA + H2O
I...10....0....10........
add.......x.............
C..-x....-x....+x
E...10-x..0....10+x
Substitute the E line into the Henderson-Hasselalch equation and solve for x = millimols KOH that must be added. Convert to grams KOH.
Post your work if you get stuck.
How many grams of solid KOH must be added to 100ml of a buffer solution which is 0.1M each with
respect to the weak acid HA and its potassium salt KA in order to make the pH of the solution 6.0?
2 answers
Yes... Got the answer 0.458 g.. Thank you...
0 answers