Asked by Anonymous

How many grams of a solid mixture containing strontium chloride would one need to make 558 mL of a 0.100 M strontium chloride solution, if the solid mixture contains 58.6% strontium chloride by weight
Answered by DrBob222
How many mols do you need? That's M x L = mols. 0l00 x 0.558 L = ?
Then grams = mols x molar mass = ?
That's grams you need if the SrCl2 is 100%. It isn't so you need ?g from above/0.586 = ??
Answered by Masivuye
6.62 g
Answered by Masivuye
8.85 g
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