Asked by Ali Alkhfajy

How many grams of solid NaOH are required to prepare 500 ml of a
0.04 M solution? (b) Express the concentration of this solution in terms of
N, g/liter, % w/v?

Answers

Answered by Anonymous
0.02 moles is required=0.5L*0.04 M

500mL=0.5L

0.02 moles*(39.997g/mole)=???


(???/500)*100= w/v %

Answered by Anonymous
Only 1 equivalent. So, M is equal to N

g/L= ???/0.5L


Answer should have only one significant figure, but you can include 3.
Answered by Ali Alkhfajy
ALLAH HU AKBAR
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