Asked by maddie
how many grams of solid calcium oxide must react with excess water to liberate the same quantity of heat as does the combustion of 24.4 l of methane gas (CH4), measures ar 24.7 c and 753 torr?
CaO +H2O --> Ca(OH)2
Delta H = -65.2 KJ
CH4 + 2O2 --> CO2 +2H20
Delta H=-890.3 KJ
i just do not understand how to do this problem
CaO +H2O --> Ca(OH)2
Delta H = -65.2 KJ
CH4 + 2O2 --> CO2 +2H20
Delta H=-890.3 KJ
i just do not understand how to do this problem
Answers
Answered by
DrBob222
The kJ for 16 grams CH4 is -890.3. How many mols CH4 do you have? That's PV = nRT. How many grams is that of CH4? That's n = grams/molar mass. You know molar mass and mols, solve for grams CH4,
Then -890.3 kJ x (grams CH4/16) = ? kJ for that reaction for that many grams CH4.
Now, 56 g CaO will produce 65.2 kJ of heat. Finally,
56 g CaO x (heat from CH4/65.3) = ?
Then -890.3 kJ x (grams CH4/16) = ? kJ for that reaction for that many grams CH4.
Now, 56 g CaO will produce 65.2 kJ of heat. Finally,
56 g CaO x (heat from CH4/65.3) = ?
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