Asked by Fernando
Solve for x: logx +log(x-5)=2
Answers
Answered by
Steve
since log a + log b = log ab,
log x(x-5) = 2
x(x-5) = 10^2 = 100
x^2 - 5x - 100 = 0
x = (5 ± √425)/2
= 5/2 (1 ± √17)
log x(x-5) = 2
x(x-5) = 10^2 = 100
x^2 - 5x - 100 = 0
x = (5 ± √425)/2
= 5/2 (1 ± √17)
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