Asked by Anonymous

Solve:

logx^3 - log2 = log(2x^2)
Answered by Reiny
logx^3 - log2 = log(2x^2)
logx^3 - log(2x^2) = log2
log(x^3/(2x^2)) = log2
log(x/2) = log2
x/2 = 2
x = 4
Answered by Raphael
Log x³ - log 2 = log (2x²)
Log x³ - log 2 = log (2×x²)
Log x³ - log 2 = log 2 + log x²
Log x³ - log x² = log 2 + log 2
Log (x³/x²) = log (2×2)
x^3-2 = 4
x=4
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