Asked by Kathy
solve for x:
logx (6+4x-x2) = 2
logx (6+4x-x2) = 2
Answers
Answered by
bobpursley
Hmmm. I did it by inspection. IF x is 3, then Logx (6-4x-x2)=log3 (6+12-9)=
log3(9)=2
How did I do it? In highscool, bases are integers. 1 is not allowed, 2 wont work, and three does, ... In the real world, bases can be any number. Frankly, I don't see an easy way to do it without this type of arguement.
log3(9)=2
How did I do it? In highscool, bases are integers. 1 is not allowed, 2 wont work, and three does, ... In the real world, bases can be any number. Frankly, I don't see an easy way to do it without this type of arguement.
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