Question

show that logx,logx^2,logx^3,logx^4...is n(n+1)logx/2

Answer 1

1+2+3+...= n(n+1)/2
logx + logx^2 + ... + logx^n = 1logs + 2logx + ... + n logx
= (1+2+3+...+n)logx
= n(n+1)/2 logx