Question

logx^2{base3}=-8

show that x=1/27

Answer 1

not that dificult
logx^2=-8
x^2=3^-8
x^2=3^(-2)^3
power 2 cancel out we have
x=3^-3
x=1/3^3
x=1/27

Answer 2

or
log₃ x^2 = -8
2 log₃ x = -8
₃ x = -4
x = 3^-4
x = 1/81 not 1/27

check with calculator
if x = 1/27
₃ (1/27)^2
= 2₃ (1/27)
= 2(-3)
= -6
≠ -8

1/81 does check out.

Answer 3

oh yeah i did not see that thanks.....