Asked by Ekingdeft
If Logx-6 base3=2y and Logx-7 base2=3y, show that x^2-13x+42=72y
Answers
Answered by
Reiny
You have a typo.
the right side of your equation should say 72^y
log<sub>3</sub>(x-7) = 2y --> 3^(2y) = x-7
log<sub>2</sub>(x-6) = 3y --> 2^(3y) = x-6
then
LS = x^2 - 13x + 42
= (x-6)(x-7)
= ( 2^(3y) ) ( 3^(2y) )
= (8^y)(9^y)
= 72^y
= RS
the right side of your equation should say 72^y
log<sub>3</sub>(x-7) = 2y --> 3^(2y) = x-7
log<sub>2</sub>(x-6) = 3y --> 2^(3y) = x-6
then
LS = x^2 - 13x + 42
= (x-6)(x-7)
= ( 2^(3y) ) ( 3^(2y) )
= (8^y)(9^y)
= 72^y
= RS
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.