Asked by Nicole
logx+log(x+3)=1
Answers
Answered by
Reiny
log(x(x+3)) = 1
x(x+3) = 10^1
x^2 + 3x - 10 = 0
(x+5)(x-2) = 0
x = -5 or x = 2 , but in logx , x > 0, so
x = 2
x(x+3) = 10^1
x^2 + 3x - 10 = 0
(x+5)(x-2) = 0
x = -5 or x = 2 , but in logx , x > 0, so
x = 2
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