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collins
Questions (23)
A body of mass 10kg is to be raise from the bottom to the top of an inclined plane 5m long and 3.0m off the ground at the top
1 answer
600 views
A train at station P accelerate uniformly from rest until it attain a speed of 100 k/h. It then continues at the speed for some
0 answers
561 views
Using elimination method solve 2/x-3/y=1, 8/x+9/y=1/2
1 answer
454 views
explain the course of religious wars in buganda
2 answers
531 views
Question. Find the greatest common divisor d of 159 and 51, and find integers x and y solving the equation 159 x + 51 y = d .
Ans
1 answer
623 views
sir steve have been looking for that book you said i should buy over the net the whol,night to get,the raw file study them but i
2 answers
474 views
k/k^5=logk find k
4 answers
490 views
write down the expansion of (1+x-x^2)^6 in Ascending other please show full working!
2 answers
490 views
in the expansion of (1+x)^(n+1) the coefficient of x^4 is 6k and in the expansion of (1+x)^(n-1) the coefficient of x^2 is
7 answers
602 views
integrate:xtan^-1/(1+x^2)^2....working plz
1 answer
368 views
integration i need help
integrate:(1-e^x)^5/e^4x..plz show full working
1 answer
364 views
please help solve these
questions (1a). The gravitational field strength g on the earth’s surface is 9.8N/kg. explain what this
0 answers
575 views
please help solve these
questions (1a). The gravitational field strength g on the earth’s surface is 9.8N/kg. explain what this
1 answer
771 views
please help solve these
questions (1a). The gravitational field strength g on the earth’s surface is 9.8N/kg. explain what this
1 answer
731 views
(1a). The gravitational field strength
g on the earth’s surface is 9.8N/kg. explain what this means.(b) Using the law of
1 answer
901 views
(2). Determine the velocity which a body released at a
distance r from the center of the earth when it strikes the earth surface.
1 answer
402 views
In the figure, a radar station detects an airplane approaching directly from the east. At first observation, the airplane is at
1 answer
942 views
If y=2x^2-21x^2+60x+6
what is the value of x? dx^2/dy^2=0
2 answers
441 views
use the first principle to obtain the differencial coefficient
y=1/(2x-1)
6 answers
405 views
integrate secxdx
1 answer
497 views
evaluete 1+7/3
1 answer
233 views
two regular polygons of the same number of sides have sides 5 ft. and 12 ft. in length, respectively. what is the length of the
1 answer
590 views
the probability that a radomly chosen potential customer will make a purchse is 0.20if a sales man calls on 6 customers .what is
1 answer
462 views
Answers (142)
a+5d=9375....(1) a+4d=375....(2) find a&d wont be difficult now just subtract 1 from 2 t9=a+8d
yeah "sometimes"
use hero's formula sum all the side a+b+c/2=s now evaluate area=√[s(s-a)(s-b)(s-c)] good luck
let the digit be abc a+b+c=20 b=1/4(a+c) 100a+10b+c=100b+10c+b+198 now solve for abc and good luck
forget about that grammer just smile with your solution and learn to use your dictionary although i am not a fan of english But In mathematics, an extraneous solution (or spurious solution) is a solution, such as that to an equation, that emerges from the
may be if you put your parentheses well i might be able to help you,because i dont understand you mathematical write up
x/(5x+4)=3 x=3(5x+4) x=15x+12 x-15x=12 -14x=12 -7x=6 x=-6/7 there you go find algebra difficult?
what do u me by exponent 2 is it h=-16t²+60t?
Frictional force = μ mg
profit=sp-cp
find ur mean let say ur mean is n (n-2)²+(n-24)²till u reach d last no/total
4m⁴-24m³+33m²+9m-9=0 re-write the polynomial equation as: 4m⁴-24m³+36m²-3m²+9m-9=0 because: 36m²-3m²=33m² re-grouping (4m⁴-24m³+36m²)-(3m²-9m)-9 factor out 4 4(m⁴-6m³+9m²)-(3m²-9m)-9 note: m⁴-6m³+9m²=(m²-3m)² therefore,we ve:
5-4²+6-2²-1=5-16+6-4-1 =5+6-16-4-1 =11-5-16=-10 not true
oooh what wrong with me it tan15=x/2.2m x=2.2m*tan15
sorry it would be 1/2 of 30degree=15degree so x=2.2m/tan15 total distance =2*x
i don't know where the angle meet up so i just pick it from btw d leg here where x is the leg tan30=2.2/x x=2.2m/30
let the distance travel by both be a&b a has a distance of d1 like wise b speed=distanc/time d1=2v d2=4v total distance d1+d2=180 2v+4v=180 6v=180 v=30 d1=2*30 d1=60 d2=4*20 d2=120 now start u get u starting not that there meet at same point so now
b=2/5 p=1/5 remaining are wind wood=1-2/5-1/3=4/15 clarinet=1/2(4/5)=2/15 tubas=1/8(b)=1/8(2/5)=1/20 let m be the no of tubas m=240/20 m=??
the increasing rate or r^3 is 12 time of increasing rate of r d/dt(r^3)=12dr/dt 3r^2dr/dt=12dr/dt divde through by 3 r^2dr/dt=4dr/dt r^2dr/dt-4dr/dt=0 dr/dt(r^2-4)=0 r^2-4=0 (r-2)(r+2)=0 r=2 or r=-2 that went awesome now just have it in mind that any
y=kx 32=4k k=8 huh?
f=26+b...(1) (b-3)=1/3(f-3) 3b-9=f-3 3b=f-3+9 3b=f+6 3b-6=f 3b-6=26+b 2b=26+6 2b=32 b=16 F=26+16 f=42
sorry it should be 15/t-20/t=8/60
speed=distance/time 20=d/t 20t=d t=d/20 and 15t=d d=15/t so amy finish 15/t-20/t=8/20 find t then you can get their distance
solve each equation? hmmm-well Suggested solution log3^n+log9=log69 log3^n=log69-log9 n=(log69-log9)/log3 find n then round up
use y=mx+c now x1=4 and x2=-1 y1=-3 and y2=1 x1=4&y1=-3 sub into equation of the line -3=m*4+c 4m+c=-3...(1) now x2 and y2 1=-m+c -m+c=1...(2) subtract 2 from 1 5m=-3 m=-4/5 when perpendicular it is now 5/4
i would be very happy to help if you would show me your suggested answer...
see [(42(x^2)-4pi(x^2)] 21*2(x^2)=42(x^2) rit? 2*2(x^2)pi=4(x^2)pi rit? [(21*(2x^2)-(2x^2)*2pi)] bring (2x^2) out you get (2x^2)(21-2pi) do you undestand now
a+b=76...(1) a-b=38......(2) adding 1 and 2 together you get a+b+a-b=76+38 a+a+b-b=114 2a=114 a=114/2 a=57 plug a into any of the equation e.g 57+b=76 b=76-57 b=19 57-b=38 -b=38-57 -b=-19 b=19 i guess u meant a/b=57/19=3...
30/100*60=30*60/100=??
you are welcome
i agree with u so now can u solve it
hmmm never mind u gave me a wrong formula A=p(1+r%)^n A=20000(1+5.5/100)^3 A=20000(1+0.055)^3 A=20000*(1.055)^3 now do what i told you recall that i=A-p
what could be the problem plug in those value A=20000(1+5.5/12)^3*12 A=20000(1+0.4583)^36 A=20000*(1.4583)^36 Puch ur calculator for (1.4583)^36 And multiply by 20000 and wuehi we are done!!!
draw a vertical line to represent the radio mast,and then a horizontal 53m away from the radio mast.and then also a diagonal line from the angle of elevation to the top of the radio mast then tan63=h/53 find h?
log(ab)=loga+logb log3x+log[3(x-2)]=1 log[(3x)(3x-6)]=1 (3x)(3x-6)=10^1 9x^2-18x-10=0 find x and see if you would arrive at that
telling you there is a total let the width 10w^2+10w*4=1050 now solve for w
telling you there is a total let the width 10w^2+8w*4=1050 now solve for w
reciprocal of -1/6 =6 and that of 1/2=2 a=-6 b=2 a+b=x -6+2=x x=-4 y=a*b y=-6*2 y=-12 z=2(a)/b z=2*-6/2 z=-6 now x+y+z=??
you can do that just 6-17=???
use these formulea a^2=b^2+c^2-(2bcCosA) then to get angle C sinA/a=sinC/a...(1) to get angle B sinB/b=sinC/c....(2) there you go a big hint
Physics-huh? i can,t see any problem to try them if i can..
ooh i did not read that poor reading yeah
A=Lw A=4*30 A=120square unit
from sir steve work remeber that 6th term is 6th term=a+5d =24+5*8 =64
x/4+2x/20=700...mucg easier now rit? just find x
i made a i little error in my previous post here (1/4)x+(1/4*2/5)x=700 solve for x
(1/4)x+(1/4*1/2)x=700
oops dx/dp not dy/dp
if it's derivative take the 'p' as a constant dy/dp=2x-4p
