Asked by jameson
A stone is aimed at a cliff of height h with an initial speed of v = 60.0 m/s directed 25.0° above the horizontal, as shown in the Figure below by the arrow. The stone strikes at A, 4.30 s after launching. What is the height of the cliff?
Answers
Answered by
alicia
D= ViT + 1/2aT^2
D= (60)4.3+4.9(4.3^2)
D= 348.6 M
D= (60)4.3+4.9(4.3^2)
D= 348.6 M
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