Asked by Anonymous
A stone is thrown from a cliff top with a vertical velocity of 50 m/s and horizontal velocity of 20 m/s.
What is its resultant velocity?
At what angle above the horizontal is it thrown?
What is its resultant velocity?
At what angle above the horizontal is it thrown?
Answers
Answered by
Henry
Xo = hor. = 20m/s.
Yo = ver. = 50m/s.
tanA = Yo / Xo = 50 / 20 = 2.5,
a = 68.2 Deg.
Vo = Xo / cosA = 20 / cos68.2 = 53.85m/s @ 68.2 deg.
Yo = ver. = 50m/s.
tanA = Yo / Xo = 50 / 20 = 2.5,
a = 68.2 Deg.
Vo = Xo / cosA = 20 / cos68.2 = 53.85m/s @ 68.2 deg.
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