Asked by pavatharani
a stone falls from a cliff and travels 34.3m in the last second before it reaches the ground. calculate the height of the cliff.
Answers
Answered by
drwls
Let T be the total time to fall.
Let H be the cliff height.
You must solve two equations in two unkonowns. No big deal.
H = (1/2) g T^2
H - 34.3 = (1/2) g (T-1)^2
First eliminate H
34.3 = (g/2)[T^2 - T^2 +2T -1]
= (g/2)(2T-1)
(2T-1) = 7.0 s
T = 4.0 s
Then solve for H. I get 78.4 m.
Let H be the cliff height.
You must solve two equations in two unkonowns. No big deal.
H = (1/2) g T^2
H - 34.3 = (1/2) g (T-1)^2
First eliminate H
34.3 = (g/2)[T^2 - T^2 +2T -1]
= (g/2)(2T-1)
(2T-1) = 7.0 s
T = 4.0 s
Then solve for H. I get 78.4 m.
Answered by
Working hard on physics
I didnt get it
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