Asked by LALAINE
A STONE IS DROPPED FROM A CLIFF SOME HIGH. DISREGARDING AIR RESISTENCE, (a) HOW LONG DOES IT TAKE THE STONE TO REACH THE GROUND? (b) WHAT IS ITS SPEED WHEN IT STRIKE THE AROUND?
Answers
Answered by
drwls
You need to provide numbers like the cliff height. "Some high" won't cut it.
Please turn off your caps lock. It is like being yelled at.
Please turn off your caps lock. It is like being yelled at.
Answered by
tchrwill
I assume you are looking for a general expression for the time it takes an object to fall from a cliff of height "h".
From h = Vot + gt^2/2
where H = the height of the cliff
Vo = the initial velocity = 0
g = acceleration due to gravity and t = the time of the fall.
Solving for t yields
t = sqrt(2h/g).
Choose your "h" and you have the time of the fall.
From h = Vot + gt^2/2
where H = the height of the cliff
Vo = the initial velocity = 0
g = acceleration due to gravity and t = the time of the fall.
Solving for t yields
t = sqrt(2h/g).
Choose your "h" and you have the time of the fall.
Answered by
nadia
h=100m t=200/9.8= 20.408 sec.
Answered by
Anonymous
Nothing foo
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