Question

A stone is projected at a cliff of height h with an initial speed of 48.0 m/s directed 60.0° above the horizontal. The stone strikes at A, 5.20 s after launching. Find the height, h, of the cliff. Find the speed of the stone just before impact at A. Find the maximum height H reached above the ground.

Answer 1

Height of the cliff, h:
h = 48.0 m/s * 5.20 s * sin(60.0°) = 144 m

Speed of the stone just before impact at A:
v = 48.0 m/s * cos(60.0°) = 24.0 m/s

Maximum height H reached above the ground:
H = 48.0 m/s * 5.20 s * sin(60.0°) - (1/2) * 9.8 m/s^2 * (5.20 s)^2 = 144 m - 131.44 m = 12.56 m