Question

Two motorcycles are traveling due east with different velocities. However, four seconds later, they have the same velocity. During this four-second interval, cycle A has an average acceleration of 1.8 m/s2 due east, while cycle B has an average acceleration of 3.8 m/s2 due east. By how much did the speeds differ at the beginning of the four-second interval?
Which motorcycle was moving faster?

Answer 1

If cycle A had velocity a, and
cycle B had velocity b,

a + 1.8*4 = b + 3.8*4
a-b = 8

a was going 8m/s faster than b

makes sense, since b accelerated faster, yet wound up with same speed.

Answer 2

-7.36