Asked by Anonymous
                 Two motorcycles are traveling in opposite directions at the same speed when one of the 
cyclists blasts his horn, which has frequency of 544 Hz. The other cyclist hears the
frequency as 522 Hz. If the speed of sound in air is 344 m/s, what is the speed of the
motorcycles
            
        cyclists blasts his horn, which has frequency of 544 Hz. The other cyclist hears the
frequency as 522 Hz. If the speed of sound in air is 344 m/s, what is the speed of the
motorcycles
Answers
                    Answered by
            bobpursley
            
    http://en.wikipedia.org/wiki/Doppler_effect  Use that equation.
    
                    Answered by
            drwls
            
    The motorcyclists are going in opposite directions, away from one another. Each has speed v and the sound speed is a. The received frequency is
522 = 544*(a-v)/(a+v)
(344-v)/(344+v) = 0.95956
344-v = 330.09 + 0.94956v
1.94956v = 13.912
v = 7.1 m/s
    
522 = 544*(a-v)/(a+v)
(344-v)/(344+v) = 0.95956
344-v = 330.09 + 0.94956v
1.94956v = 13.912
v = 7.1 m/s
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