Asked by lianna
Two motorcycles are at rest and are separated by 24 ft they start at the same time and same direction , the one in the back is having acceleration 3 ft/ sec^2 and the one in front is 2 ft/sec^2 can be machine at the back overtake in front?
A. How long thus it takes to overtake?
B. How far this is goes before it cathes up?
C. How fast its machine going at the same time on overtaking?
A. How long thus it takes to overtake?
B. How far this is goes before it cathes up?
C. How fast its machine going at the same time on overtaking?
Answers
Answered by
bobpursley
a. d1=.5 (2)t^2
d2=.5 (3)t^2 +24
but d1=d2 then
put d1, d2 in and solve for time t.
b. use the d2 equation
c.v2=3*t^2
d2=.5 (3)t^2 +24
but d1=d2 then
put d1, d2 in and solve for time t.
b. use the d2 equation
c.v2=3*t^2
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.