Asked by Anonymous
Two motorcycles are at rest and separated by 24.5 ft. They start at
the same time in the same direction, the one in the back having an
acceleration of 3 ft. per sec2, the one in the front going slower at an
acceleration of 2 ft. per sec2.
(a) How long does it take for the faster cycle to overtake the slower?
(b)How far does the faster machine go before it catches up?
(c) How fast is each cycle going at this time?
the same time in the same direction, the one in the back having an
acceleration of 3 ft. per sec2, the one in the front going slower at an
acceleration of 2 ft. per sec2.
(a) How long does it take for the faster cycle to overtake the slower?
(b)How far does the faster machine go before it catches up?
(c) How fast is each cycle going at this time?
Answers
Answered by
oobleck
(a) 1/2 * 3t^2 = 24.5 + 1/2 * 2t^2
(b) the above expressions are the distances covered.
(c) v = at for each cycle.
(b) the above expressions are the distances covered.
(c) v = at for each cycle.
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