distance covered by faster driver --- x km
distance covered by slower driver --- 320-x km
The must have driven the same abount of time, so
x/95 = (320 - x)/65
65x = 30400 - 95x
160x = 30400
x = 190
time = 190/95 = 2 hrs
check:
time of faster driver = 190/95 = 2
time of slower driver = (320-190)/65 = 2
YEAHH
Two motorcycles travel toward each other from cities that are about 320km apart at rates of 95km/hr and 65km/hr. They started at the same time . In how many hours will they meet?
1 answer