mols NaOH = M x L = ?
The rest of it I don't get. In quant ABOUT 1g of the acid won't get it. You filtered it, also. Does that mean all of the about 1 g did not dissolve? However, you know that whatever you did to the acid that mols NaOH = mols acid.
Run # Volume NaOH used (mL)
1 4.1
2 4.3
3 2.8
Concentraion of NaOH: 0.113 M
pH of acid: 2.84
the questions are:
#moles of NaOH: ?
initial acid concentration: ?
Determine the Ka and pka of the weak acid: ?
So here is what I did:
Shaked for several minutes about 1 g of the acid with 120 ml of distilled water. Filtered the solution into a clean beaker. Determined the concentration of the acid in the filtrate by pipetting a 25 ml aliquot into a clean flask and titrating it with 0.1 M sodium hydroxide.
Placed about 30 ml of the acid solution from part a in a 50 ml polystyrene breaker and found its ph using a ph meter.
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