Asked by Anonymous
What volume of 0.1 M NaOH is required to neutralize 30 mL of 0.1 M HCl?
Answers
Answered by
Devron
Calculate the number of moles for HCl in a 30mL sample of 0.1M HCl
30 x10^-3 L*(0.1M)=moles of HCl
The number of moles of HCl/the molarity of NaOH will give you the volume needed in L.
volume in L=moles of HCl/0.1 M NaOH
*** Multiply the volume by 10^3 if you need to report the volume in mLs.
30 x10^-3 L*(0.1M)=moles of HCl
The number of moles of HCl/the molarity of NaOH will give you the volume needed in L.
volume in L=moles of HCl/0.1 M NaOH
*** Multiply the volume by 10^3 if you need to report the volume in mLs.
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.