Asked by Anonymous
What volume of 0.130 M NaOH is needed to neutralize 4.00 g of benzoic acid?
Answers
Answered by
DrBob222
moles benzoic acid = grams/molar mass
moles NaOH = moles benzoic acid
M = moles/L. You know M and moles. Calculate L.
moles NaOH = moles benzoic acid
M = moles/L. You know M and moles. Calculate L.
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