What volume of 0.20M NaOH will contain 1.00g of NaOH

2 answers

mol of Na O H = 23+16 + 1 = 40 grams
so 1 gram is 1/40 mol = .025 mol

.025 mol = .2 mol/liter * x liters
so
x = .025/.2 = .125 liters or 1/8 liter
or 125 mL.
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