mol of Na O H = 23+16 + 1 = 40 grams
so 1 gram is 1/40 mol = .025 mol
.025 mol = .2 mol/liter * x liters
so
x = .025/.2 = .125 liters or 1/8 liter
What volume of 0.20M NaOH will contain 1.00g of NaOH
2 answers
or 125 mL.