Question

What volume of 1.00 M NaOH would be required to neutralize 77.4 mL of 5.4 M HCl? Round to two places after the decimal point and keep it in mL

Answer 1

mols HCl = M x L = ?
mols NaOH = mols HCl

Then M NaOH = mols NaOH/L NaOH