Asked by Corso



What volume of 1.00 M NaOH would be required to neutralize 77.4 mL of 5.4 M HCl? Round to two places after the decimal point and keep it in mL
Answered by DrBob222
mols HCl = M x L = ?
mols NaOH = mols HCl

Then M NaOH = mols NaOH/L NaOH
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