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fenerbahce
Questions (15)
What is the pH of a 0.250 M NH4Cl solution? Kb for NH3 = 1.8 × 10−5.
Thank you.
0 answers
659 views
I have a question.
For Fe|Fe^+2 (1M)| Cu|Cu^+2 (1M why did you use Fe^2+ ==> Fe^3+ + e Eo = -0.771 ? instead of: Fe ---> Fe^+2 +
2 answers
314 views
I'm adding this to my previous question..in our textbook its says Ecell=Ecathode-Eanode. That's my values were smaller. But you
1 answer
387 views
the measured cell voltages are supposed to be smaller than the theoretical cell voltages, but when I'm calculating the
1 answer
543 views
Calculate the reduction potential of the following solutions:
a- 1 M CuSO4 b- 1 M FeSO4 c- 0.1 M CuSO4 I'm now the same answer as
1 answer
634 views
Please...how do you calculate the reduction potential for 1 M CuSO4? I've been trying for hours......!!
3 answers
452 views
How do you calculate the theoretical cell voltage?
1) Zn|Zn^+2 (1M)| Cu|Cu^+2 (1M) okay so by looking at example this example
4 answers
4,133 views
How do you calculate the theoretical cell voltage?
1) Zn|Zn^+2 (1M)| Cu|Cu^+2 (1M) 2) Cu|Cu^+2 (1M)| Zn|Zn^+2 (1M) 3) Fe|Fe^+2
1 answer
898 views
How do you calculate the theoretical cell voltage?
1) Zn|Zn^+2 | Cu|Cu^+2 2) Cu|Cu^+2 | Zn|Zn^+2 3) Fe|Fe^+2 | Cu|Cu^+2 4)
2 answers
507 views
[NaOH]= 0.113M
V of NaOH needed to titrate = 0.0037L V of unknown weak organic acid = 0.025L Find: The initial concentration of
3 answers
550 views
Run # Volume NaOH used (mL)
1 4.1 2 4.3 3 2.8 Concentraion of NaOH: 0.113 M pH of acid: 2.84 the questions are: #moles of NaOH: ?
1 answer
543 views
Okay let me write it this way.
I mixed 30 mL of 0.1 M Acetic Acid and 15 mL of 0.1 M Sodium Hydroxide and measured the pH. Then I
2 answers
404 views
How do I calculate the initial concentraion of an acid?
1 answer
455 views
acetic acid: 0.1 M 30ml
hydrochloric acid 0.1 M 5 ml sodium hydroxide 0.1 M 15 ml Buffer + 5ml of: 1.91 ph ph (measured): 4:52 ph
4 answers
913 views
1) Aluminum Chloride- Red- PH: 4.0
2) Sodium Carbonate - Violet- PH: 9.5 Ammonium Acetate - Yellow - PH: 6.5 the question is:
2 answers
529 views
Answers (11)
the cell is written like that in the report sheet so that's why I wrote it like that
Thank you very much..And I posted another question, the most important ones that I don't know how to do.
Please help me I've been trying for the whole day!
******HOW DO YOU CALCULATE THE REDUCTION POTENTIAL OF 1 M CuSO4 AND 0.1 M CuSO4? NOTE: THE REDUCTION POTENTIAL OF 1M Zn(NO3)2 IS -0.76 V. I'M REALLY STUCK.
NOTE I calculates by using the above example
but for example for question 4 Zn is 1 M and Cu is 0.1 M will that make a difference? and can you just do one example I want to see if I'm on the right track. Thanks.
Ok How do I find the initial concentration of the acid?
I how you answers this but what is "c" HAc? NaAc?
Ok. Thank you so much Dr. Bob
Okay let me write it this way. I mixed 30 mL of 0.1 M Acetic Acid and 15 mL of 0.1 M Sodium Hydroxide and measured the pH. Then I added 5 mL of 0.1 M NaOH to this buffer and measured the pH. It's asking me: Show the calculations for the pH of the buffer
if it doesnt exist should I write NH3 + H2O ---> NH4OH + HA ? thank you.