Asked by RAD

Solve the equation. Round answers to the nearest hundredth.

log(7x+1)=log(x-2)+1

Answered by Steve
one way:
log(7x+1)=log(x-2)+log(10)
7x+1 = (x-2)(10) = 10x-20
3x = 21
x = 7

other way:

log(7x+1)-log(x-2) = 1
log ((7x+1)/(x-2) = 1
(7x+1)/(x-2) = 10
7x+1 = 10(x-2)
. . .

Check:
log50 = log5 + log10
Answered by Anonymous
x/(x^(2)-4)+5x/(x^(2)-7x+10)
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