Asked by Ketrina
"Solve each equation. Round your answers to the nearest ten-thousandth." (These are my directions)
Here is the equation: 3^n + 9 = 69
How do I solve this getting the answer asked for?
Here is the equation: 3^n + 9 = 69
How do I solve this getting the answer asked for?
Answers
Answered by
collins
solve each equation?
hmmm-well Suggested solution
log3^n+log9=log69
log3^n=log69-log9
n=(log69-log9)/log3
find n then round up
hmmm-well Suggested solution
log3^n+log9=log69
log3^n=log69-log9
n=(log69-log9)/log3
find n then round up
Answered by
Reiny
You cannot take log of individual terms, you have to take log of both sides.
i.e. log (3^n + 9) = 69
but , why not just do this:
3^n = 60
now log both sides, and use log rules:
n log3 = log60
n = log60/log2 = appr 3.727
check:
3^3.727 + 9 = 69.01100 , close enough to 69
if you meant:
3^(n+9) = 69
(n+9)log3 = log 69
n+9 = log 69/log3
n = log69/log3 - 9
i.e. log (3^n + 9) = 69
but , why not just do this:
3^n = 60
now log both sides, and use log rules:
n log3 = log60
n = log60/log2 = appr 3.727
check:
3^3.727 + 9 = 69.01100 , close enough to 69
if you meant:
3^(n+9) = 69
(n+9)log3 = log 69
n+9 = log 69/log3
n = log69/log3 - 9
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.