Asked by Elizabeth
Solve the equation. Leave answer in simplest radical form.
n^2-2n+1=5
n^2-2n+1=5
Answers
Answered by
DW
n^2-2n-4=0
a=1 b=-2 c=-4
then use quadratic formula
x=(-b+sqrt(b^2-4ac))/(2a)
x=(-b-sqrt(b^2-4ac))/(2a)
x=1+sqrt(5)
x=1-sqrt(5)
a=1 b=-2 c=-4
then use quadratic formula
x=(-b+sqrt(b^2-4ac))/(2a)
x=(-b-sqrt(b^2-4ac))/(2a)
x=1+sqrt(5)
x=1-sqrt(5)
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